This is the most simple answer to the prob of two people having the same
birthday:

Equivalent to the probability that with 12 people in a room, none have the
same birth month. The first guy can have any month, the second can only
choose from the remaining 11, the third 10, etc., so the probability is

1 * 11/12 * 10/12 * ... * 1/12 = 11!/12^11 = 0.0054% or almost 0.


Thanx

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